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2015-04-02T08:49:57+05:30

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⇒Radius of the soap bubble= 0.02 m ∛ ⇒Surface tension of the soap solution=0.03N/m ⇒Let us find the surface area. so , ⇒surface area = 4(π) r² .⇒=4×22/7×(0.2 )² ⇒No .of surface area of the soap bubble = 2 ( Outer and inner area ) ⇒Surface area is given as TΔS per surface ⇒Let us next find the total surface area =2 (TΔS) ⇒E = 2 ×0.03 × 4×22/7 × (0.2 )² Joule.....is the ans.
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2015-04-02T13:37:24+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Radius of bubble, r = 0.02m
surface tension, T = 0.03N/m

Work required = surface area×surface tension
surface area = 4πr²
number of surfaces = 2
⇒ S = 2×4×3.14×0.02² = 0.01 m²

Work = 0.01×0.03 = 0.0003 J = 3×10⁻⁴ J
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