Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

For the area of a triangle, you have the formula, (s(s-a)(s-b)(s-c))^1/2 where s= (a+b+c)/2 but this is aright angled triangle, so you can easily apply the formula area=1/2axb, where a=12, b=5 for altitude, you can imagine it divides the hypotenuse into 2 parts x and 13-x h,x,5 (h is length of altitude) form a right angled triangle whereas h,13-x,12 form another. using pythagoras theorm, solve for x. then find the altitude. the shortest altitude is the altitude to the hypotenuse.

You can find are of any triangle by HERON'S fromula if all its sides are known. Here Sides are - 5 cm, 12 cm and 13 cm. So, s = (a+b+c+)/2 where a,b, and c are sides of triangle s = (5+12+13)/2 = 30/2 = 15 Area = Area = So, Area = 30

And the smallest height will be on the largest base. So here the largest side is 13 cm. So by area formula we have Area = 1/2 *base * height But area = 30 so, 30 = 1/2 * 13 *height height = 60/13 = 4.615 cm