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Option C is correct i.e. CH3  and  CH3CO+
Halogen group
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but the answer is given option b..... ch3 or ch3c(+)o
this is nucleophile not electrophile
The Brainliest Answer!
In friedel-Ccrafts alkylation of benzene electrophile is CH3+
in friedel-crafts acyation of benzene electrophile is CH3CO+
fridal craft reaction is use to attach substituents to an aromatic ring

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