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Given-OA=6cm OC=8cm now in trnglAOD and trnglCOD, angle AOD =angle AOC(since diagonals bisect each other) OD is common AO=OC(since diagonals bisect each other) ⇒ trnglAOD ≡ trnglCOD, (SAS postulate) we know that area of similar triangles is the ratio of the squares on their corresponding sides ⇒(area of trnglAOD÷ area of trngl COD),=OA²÷OC² =6³÷8² =36÷64 =9:16