Answers

2015-04-03T17:38:52+05:30
the probability that at least three of them will be busy is equal to=>C(6,3)*(1/10)^3 *(9/10)^3 + C(6,4) *(1/10)^4 *(9/10)^2 + ... + C(6,6) *(1/10)^6
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Wat is the answer .... Its trivial , can't u come up wit definite answer....
2015-04-06T19:45:37+05:30
Given :⇒Probability ( Busy telephone numbers ) = 1 / 10. ..........! ⇒Probability ( Not busy telephone numbers ) = 9 / 10. ...............! According to the given question. ..............! To find :⇒ Probability (at least 3 of 6 are busy) = ?.................................! Sol :- Probability ( at least 3 of 6 are busy) = P ( Busy telephone numbers) /P ( Not busy telephone numbers ). ......= (1/ 10 )/(( 9/10)..= so , Probability ( at least 3 of 6 are busy) = C(6,3)(1/10)² 3 (9/(10²)3) + C(6,4) (1/10)²4 (9/10)²2 + ... + C(6,6) (1/10)² ..is the answer !
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