# An athlete completes one round of a circular round of a circular track of diameter 200m in 40s. What will be the distance covered and the displacement at the end of 2 mins 20s? With steps plse..

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by hrithi

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by hrithi

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Distance covered in one complete round ie., 40 sec.

= circumference of circle of diameter 200 m

= π 200 meters.

Distance covered in 2 mins 20 sec or 140 sec: = 200 π * 140/40 = 700 π meters

In 140 seconds, the athlete makes 3 complete rounds and runs for 20 secs after that.

in 40 secs, he runs a complete circle (covers 360°). So in 20 secs, athlete runs half-circle and covers 180°.

So at the end of 140 seconds, athlete is at the diametrically opposite end on the circular track.

The displacement = vector joining the initial position to the final position.

It magnitude = diameter = 200 meters.

= circumference of circle of diameter 200 m

= π 200 meters.

Distance covered in 2 mins 20 sec or 140 sec: = 200 π * 140/40 = 700 π meters

In 140 seconds, the athlete makes 3 complete rounds and runs for 20 secs after that.

in 40 secs, he runs a complete circle (covers 360°). So in 20 secs, athlete runs half-circle and covers 180°.

So at the end of 140 seconds, athlete is at the diametrically opposite end on the circular track.

The displacement = vector joining the initial position to the final position.

It magnitude = diameter = 200 meters.