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If a weight of 250 kgs is applied every two seconds on a lever for 6 inches that turns a turbine to generate electricity, how much electricity would be



So force 125 N/s acts
the perpendicular distance is 6(0.0252) m=0.1512m
so torque produced is t=125(0.1512)=18.9 Nm/s
so an torque acts on a coil
it produces AC current
but to find out how much current is produced  many more factors are required
0 0 0
What are those factors please?
magnetic field,number of coils,resistance of coils,temperature..and many more
Its a 100Kw turbine
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