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2015-04-05T01:09:51+05:30

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Cylindrical surface area of the roller = 140 cm * 2 π 35  cm
     = 9800π cm²  = area covered in one revolution of the roller.

total surface area of the ground = 980 * 9800 π cm² = 98 * 9.8 π m²

cost = Rs  0.75 * 9.8 * 0.98 * π  = Rs 22.63

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