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A bullet of mass 20 g moving with speed 200 m/s strikes on a piece of wood and comes to rest in 0.02 s. what is the resistance offered by the wood

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by balamohan

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by balamohan

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M = 20 grams

initial velocity = u = 200 m/s

t = 0.02 sec.

let the acceleration or deceleration = a m/sec^2

v = final velocity = u + a t

0 = 200 + a * 0.02

a = - 10, 000 m/sec^2

the resistance offered = force against the movement of the bullet

= F = m a = 20/1000 kg * 10,000 m/sec^2 = 200 Newtons.

initial velocity = u = 200 m/s

t = 0.02 sec.

let the acceleration or deceleration = a m/sec^2

v = final velocity = u + a t

0 = 200 + a * 0.02

a = - 10, 000 m/sec^2

the resistance offered = force against the movement of the bullet

= F = m a = 20/1000 kg * 10,000 m/sec^2 = 200 Newtons.