Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

A hellow iron Pipe, which is 14cm long and has its external diameter 10cm. If the thickness of the pipe is 2cm and iron weighs 10g/cm3, find the weight of

We know that volume of hollow pipe = Outer volume - Inner volume According to the question, we get :- πr²h - π(r-2)²h [As the inner radius of the pipe is 2cm less than the outer radius] = (22/7 x 5 x 5 x 14) - (22/7 x 3 x 3 x 14) = 1100 - 396 = 704 cm³

Now the weight of 1 cm³ of iron is 10gm. Thus weight of pipe = 704 x 10 = 7040 gm = 7kg 40gm

vol.of a hollow pipe= pi×R²×h-pi×r²×h= pi*h(R²-r²) here,R=5cm,r=5-2=3cm thus vol.=22/7×14×(5²-3²) =704cm³ it is given that each cm³ of iron weighs 10g. hence,the weight of 704cm³ of iron= 704×10=7040g i.e.the weight of the pipe=7040g= 7.04kg