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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

THE ANGLE OF ELEVATION OF THE INACCESSIBLE PEAK OF A HILLOCK FROM ITS FOOT IS 45 DEGREE . AFTER APPROACHING 100m ALONG A SLOPE OF THE HILLOCK , THE ANGLE

OF ELEVATION OF THE PEAK AS OBSERVED IS 60 DEGREE. FIND THE HEIGHT OF THE HILLOCK ..??( PLES HELP WITH DIAGRAM )

Just consider the hillock to be a straight verical line. let its height be h and the distance of the observer from the foot of the line be x. therefore angle of elevation from this point is 45 degrees. hence tan(45) = h/x => h/x = 1 => h=x. Now when we move closer to the foot by 100 m the angle of elevation increases to 60 degrees. therefore tan(60) = h/x-100 => √3 = h/h-100 => h*(√3 - 1) = 100√3 => h = 50*(3+√3) = 50*4.732 = 236.6 m