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2015-04-14T18:25:56+05:30

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Mass of virus = 4×10⁷ kg per kilomole
so mass of 1000 moles virus = 4×10⁷ kg
so mass of 1 mole virus = 4×10⁷/1000 =  4×10⁴ kg

mass of virus in 1cc tobacco, = 0.1mg
0.1mg = 1×10⁻⁷ kg
4×10⁴ kg contains 1 mole of virus
1 kg will have =  \frac{1}{4 \times 10^4}\ moles=2.5 \times 10^{-5}\ moles
1×10⁻⁷ kg will have = 2.5 \times 10^{-5} \times 1 \times 10^{-7}=2.5 \times 10^{-12}\ moles

number of viruses in 1 mole = 6.022×10²³ viruses
number of viruses in 2.5 \times 10^{-12} mole = 2.5 \times 10^{-12} \times 6.022 \times 10^{23}=1.505 \times 10^{12}\ viruses

So number of viruses present in 1 cc will be 1.505×10¹².
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