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A train is traveling at a speed of 90 km h(power -1).Brakes r applied so as to produce a uniform accelaration of -0.5 m s (power -2).Find how far the train

will go before it is brought to rest.



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U =  90 kmph  = 90 * 5/18 m/sec = 25 m/sec
a = -0.5  m/sec²
v = 0  as the train comes to rest.

the equation of motion is

     v²  =  u² +  2 a s
      0  =  25²  -  2 * 0.5 *  s
             s =  625 meters

1 5 1
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