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Find the value of k if the graph of the equation 3x+ky=5 passes through the point (-1,2) . For what value of k will the graph pass through (1,0) ?




Plugin the given point (-1, 2) and solve k

Second part is bit tricky :
Plugging in the point (1,0) gives
which is impossible. so there is no k such that the line 3x+ky=5 passes through (1,0)
1 5 1
updated, please see if it makes sense
it is correct or not
Question is fine, it is just that there is no k value which makes the given line pass through given point.
(thats for second part)
3x+ky = 5
when we substitute (x,y) = (-1,2) in 3x+ky = 5
3(-1)+k(2) = 5

when we substitute (x,y) = (1,0) in 3x+ky = 5
3(1)+k(0) = 5
3 = 5
therefore it is not possible to the line 3x+ky = 5 to pass into the point (1,0)

3 5 3
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