# Find the value of k if the graph of the equation 3x+ky=5 passes through the point (-1,2) . For what value of k will the graph pass through (1,0) ?

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Plugin the given point and solve

Second part is bit tricky :

Plugging in the point gives

which is impossible. so there is no such that the line passes through

The Brainliest Answer!

when we substitute (x,y) = (-1,2) in 3x+ky = 5

3(-1)+k(2) = 5

2k=8

k=4

when we substitute (x,y) = (1,0) in 3x+ky = 5

3(1)+k(0) = 5

3 = 5

therefore it is not possible to the line 3x+ky = 5 to pass into the point (1,0)