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The velocity of a train increases uniformly from 20km-h to 60km-h in 0.2h. The distance traveled by a train during this



Intial velocity u= 20 km /hr=5.56 m/s
final velocity v=60 km/hr=16.67 m/s
the train is under uniform accerleration
t=0.2 hr=12 minutes=720 secs
a=v-u/t=0.0154 m/s²
s=ut+(1/2)at²=7994.88 m=7.99488 km
2 5 2
check ur question if very thing is correct!
it is 8 km sure man wrong options
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8 km is the distance travelled
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