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Take y=(1/x)^x
take log on both sides
log y=-xlogx
diff w.r.t x
(1/y)(dy/dx)=-(log x+1)
dy/dx=y(log x +1)=(1/x)^x(log x +1)
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i.e; y=x^-x
taking log on bothsides,
differentiating w.r.t. x we get,
taking second derivative
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