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the problem is simply asking for you to list 3 'irrational' numbers. 
since the square root of any number that is not a perfect square is irrational, you can list some like: 
√2, √3, √5 
but π also works, as well as ∛2, ∛4, and the fifth root of 16.

Take a point O representing 0 on a number line. 
With some suitable scale (say 1 inch) mark a point P which represents 1 on the number line. 
At P darw a line PQ perpendicular to the number line such that PQ = 1. 
Join O to Q. 
=> OQ = √2. 
With O as center and radius = √2, cut an arc at R on the number line. 
=> OR = √2. 
Now, draw a line RS = 1 perpendicular to the number line. 
Join O to S. 
=> OS = √3 
With O as center and radius = OS cut an arc at T on the number line 
=> OT = √3 
You can continue like this and get √4, √5, √6, .... √10 and so on on the number line. 

Specifically for √10, mark a point A on the number line such that OA = 3 and draw a line AB perpendicular to the number line such that AB = 1 
=> OB = √10 (by pythagorus theorem) 
With center at O and radius = OB = √10, cut an arc at C on the number line 
=> OC = √10.
0 0 0
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