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Since cos x must always be positive

it just area under cosine function

so integral

it just area under cosine function

so integral

INT |cos x| dx (from 0 to 2pi)

= 2 * INT cos x dx (from -pi/2 to pi/2, because this would be an interval for one hump)

= 2 * sin x, evaluated from -pi/2 to pi/2

= 2 * [sin(pi/2) - sin(-pi/2)]

= 2 * [1 - (-1)]

= 2 * 2

= 4