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If a number had both a cube and square, it should have its 6th root also, since {(x)^2}^3 = x^6. (since you multiply 2*3). so it should be a perfect 6th power also. if we work it out, the numbers of numbers which have their 6th root between 1 and 2000 are only 1, 2 and 3.
1 5 1
THE NUMBERS ARE   1 ,  2  and  3 .

2 4 2
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