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where  3!=1*2*3=6
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No, It is an impossible condition.
Sum of three odd numbers results an odd number only.
So, sum of any of three given odd numbers doesn't give '30' which is an even number. So, it is not possible to get 30.
Here we cant use 3! too because 3! (3×2×1) is nothing but 6 which is an even number
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