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2015-04-18T21:41:03+05:30

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The no.s are-
7 and 5
Since 7²+5²=49+25=74.
By trial and error method.
1 5 1
Your welcome!
Can u please send me formula of "by trial and error method"
there is no formula for that its just simply selecting random data and putting in the equation to see if it satisfies or not
2015-04-18T21:53:43+05:30

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Let the required numbers be 2m+1 and 2n+1
(2m+1)^2+(2n+1)^2=74
4m^2+4m+1+4n^2+4n+1=74
m^2+m+n^2+n=18

Clearly 0\le\,m,n\,\le\,3

By working the four cases and by symmetry m,n are (m,n)=(2,3),(3,2)
therefore the required numbers are 2*2+1, 2*3+1 = 5,7
1 5 1