Answers

2015-04-22T00:43:31+05:30
Using \dfrac {q_{1}q_{2}}{4\pi \in r^{2}} and taking both charges as q1 and q2 micro coulomb, we get q1 + q2 = 9 and q1q2 = 1/5 Solve the quadratic to get q1 and q2.
0
2015-04-22T14:40:26+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
The Coulomb's law of force between two electrically charged particles :
         q
₁ , q₂ = electric charges on the two particles.
           r = distance between two particles = 0.1 m
      the particles are assumed to be point sized.
         Force F = 18 N 

        q
₁ + q₂ = 9 μ C    --- (1)

Force\ F=\frac{1}{4\pi \epsilon_0}\ \frac{q_1\ q_2}{r^2}\\\\q_1\ q_2=\frac{18*0.1^2}{9*10^9}=20*10^{-12} C,\ \ \ \ --\ (2)

  Solve the two equations to get the values of charges.
     q
₁ (9 - q₁) = 20
     q
₁² - 9 q₁ + 20 = 0
       (q
₁ - 5) (q₁ - 4) = 0

       q
₁ = 5 μ C  or  4 μ C
       q
₂  = 4 μ C  or  5 μ C
 

1 5 1