# 1. I have total of Rs 300 in coins of denomination Re 1,Rs 2 and Rs 5. The number of Rs 2 coins is 3 times the number of Rs 5 coins. The total number of coins is 160. How many coins of each denomination are with me

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Total no.of coins , x+y+z = 160 --->(2)

y=3z -->(3)

Subtituting value of (3) in (1) and (2)

1x + (2) * 3z + 5z= 300

ie; 1x + 6z+5z=300 = x + 11z=300 --> (3)

x+3z+z=160 --> (4)

Considering eqn (3) and (4)

x+11z=300

x+4z=160

then 7z=140 as x cancelled each other.

then z= 20

Now we can calculate rest...

z=20

y = 3z = 60

x+2y+5z=300

then x = 300 -120-100

= 80

x = 80

y=60

z=20

Solved...