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This is not solvable in the normal arithmetic method of
addition of the numbers given. We have to have three even numbers
or one even number and two odd numbers to get the result as an even
number. But we don’t have any odd number in the given set of numbers in
the parentheses.

We need to use an operator like a factorial or some other one, which yields an even number taking an odd number as the input.* *__Logarithm is an operator or a function which also can give an
even number__.

It is left to imaginative skill and knowledge of the person to answer this question.

* 3! + 11 + 13 = 30*

* 3! + 15 + 9 = 30*

15 + 15 + Log 1 = 30 , as Log 1 = 0 to any base.

15 + 15 + Ln 1 = 30 as Ln 1 = 0 to any base

15 + 13 + Log₃ 9 = 30, as Log₃ 9 = 2 ( base 3)

3*7 + 9 + Log 1 = 30

15 + 13 + 3!/3 = 30 using division operator in between

(1+3)! + 1 + 5 = 30

3³ + 3! / 3 + 1 = 30

9 + 1 + 5! / 3! = 30

15³/5³ + 1 + 3! / 3 = 30 using cube and division operators.

We need to use an operator like a factorial or some other one, which yields an even number taking an odd number as the input.

It is left to imaginative skill and knowledge of the person to answer this question.

15 + 15 + Log 1 = 30 , as Log 1 = 0 to any base.

15 + 15 + Ln 1 = 30 as Ln 1 = 0 to any base

15 + 13 + Log₃ 9 = 30, as Log₃ 9 = 2 ( base 3)

3*7 + 9 + Log 1 = 30

15 + 13 + 3!/3 = 30 using division operator in between

(1+3)! + 1 + 5 = 30

3³ + 3! / 3 + 1 = 30

9 + 1 + 5! / 3! = 30

15³/5³ + 1 + 3! / 3 = 30 using cube and division operators.