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The average age of husband wife who were married 8 years ago was 26 years then including two children who were twins the present age of the family is 18

yrs after how many years of their marriage were the twins born?

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Let = present age of husband Let = present age of wife Let = present age of each child

years ago, the average of husband and wife is

present average age of family is :

Since the left hand sides are equal in above equations, the right hand sides must also be equal :

That means the twins were born after years of marriage.

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Let the age of husband at the time of marriage = H yrs let the age of wide at the time of marriage = W yrs. average = (H+W)/2 = 26 yrs => H+W = 52 yrs

Present age of wife = W + 8 yrs present age of husband = H + 8 yrs present age of each of the twin = T yrs Average of the family = [ H + 8 + W + 8 + T + T ] / 4 = 18 given

H + W + 2 T + 16 = 72 yrs 52 + 2 T + 16 = 72 yrs. => T = 2 yrs As the age of the children is 2 yrs each, they were born 8 - 2 = 6 yrs after the marriage.

================== another way:

Average age of husband and wife NOW = 26 + 8 = 34 yrs. So the Sum of their ages = 68 yrs

Total age of
family = number of persons * average = 4 * 18 = 72 yrs. So sum of the ages of twins = 72 - 2 * 34 = 4 yrs.
so age of 1 child = 2 yrs. so children born after 8 - 6 = 2 yrs
after marriage