Coefficient of in is?

1
by Deleted account
Anything you all write, make sure it's an integer.
Don't say that the answer is 2cosx-2

2015-04-25T17:33:44+05:30

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Determinant value is to be found by the expansion using a column or a row.  We pick the 1st column as those expressions are complicated.

Determinant D
= x [ 0 - 2 (1+x)² ] - 1 [ 0 - (1+x)² Cos x ]  + x² [ .... ]
= - 2 x (1+x)²  + (1+x)² Cos x + x² [ ... ]

Since we want only the coefficient of  x (power 1), we ignore the last term.  We get :
- 2 x + (1 + 2 x ) Cos x

It depends whether we can treat Cos x as a coefficient of  x.  We use the MaClaurin (Taylor) series for Cos x to write it as a polynomial in x.

Cos x = 1 - x²/2  + ....     We ignore the x² term, as its power is > 1.       So we replace Cos x by 1.

Finally,  the coefficient of x :    - 2 + 2  = 0

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