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Find HCF of 1305 and 1365 :

1365 = 1305*1 + 60

1305 = 60*21 + 45

60 = 45*1 + 15

45 = 15*3 + 0

So HCF of 1305 and 1365 is 15

Next find HCF of 15 and 1530 :

1530 = 15*102 + 0

So HCF of 15 and 1530 is 15

Thus the HCF of 1305, 1365 and 1530 is 15

1365 = 1305*1 + 60

1305 = 60*21 + 45

60 = 45*1 + 15

45 = 15*3 + 0

So HCF of 1305 and 1365 is 15

Next find HCF of 15 and 1530 :

1530 = 15*102 + 0

So HCF of 15 and 1530 is 15

Thus the HCF of 1305, 1365 and 1530 is 15

1365 = 1305*1 + 60

1305 = 60*21 + 45

60 = 45*1 + 15

45 = 15*3 + 0

15 and 1530 :

1530 = 15*102 + 0

HCF of 15 &1530 is 15

HCF of 1305 &1365 is 15

So the required HCF is 15.