# ABCD is a parallelogram in which diagonals AC and BD intersect at O . if E, F, G ,H are mid points of AO, DO, CO ,BO respectively .then ratio of perimeter of quadrilateral EFGH to the perimeter of parallelogram ABCD.

2
by mmoumita18

2015-04-26T12:10:53+05:30

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Using mid-point theorm
2015-04-26T22:52:26+05:30

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We know that in a triangle the line segment joining the mid points of two sides, is parallel to the third side and measures half of the third side.

In the triangle OAB,  EF is the line joining the mid points of OA and OB.  Hence EF = 1/2  AB.

In the triangle OBC, FG is the line joining the midpoints of OB and OC.
hence,   FG = 1/2 BC

similarly,   GH = 1/2 CD      and    HE = 1/2 DA

perimeter of the quadrilateral EFGH = 1/2 AB + 1/2 BC + 1/2 CD + 1/2 DA
= 1/2 * perimeter of parallelogram ABCD.

The ratio = 1/2

we also note that EFGH is a parallelogram and has area 1/4 th of ABCD.