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Show how will you arrange three 6 Ohm resistors to get a total resistance of

i.4 ohms

ii.9 ohms

2
by confidingOz

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i.4 ohms

ii.9 ohms

by confidingOz

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The Brainliest Answer!

thus first two resistors in parallel,

1/6 +1/6 = 1/r

r = 3 ohms------ connect in series with third resistor

R =3+6 ohms = 9 ohms

for 4 ohms - two resistances in series and the third one in parallel with the combination of earlier two resistances.

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If we arrange n resistors of value R ohms in series, the effective resistance:

n R ohms

if we arrange n resistors of value R ohms in parallel, then the effective resistance: R / n ohms

for getting effective resistance of 4 ohms from 6 ohm resistors, we can put two resistors in series, and their equivalent resistance = 12 ohms. Then connect the third resistance of 6 ohms in parallel.

equivalent resistance = 12 * 6 /(12+6) = 4 ohms.

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if we connect two resistors in parallel then effective resistance = 6/2 = 3 ohms.

We connect the third resistance in series. The effective resistance: 3 + 6 = 9 ohms

n R ohms

if we arrange n resistors of value R ohms in parallel, then the effective resistance: R / n ohms

for getting effective resistance of 4 ohms from 6 ohm resistors, we can put two resistors in series, and their equivalent resistance = 12 ohms. Then connect the third resistance of 6 ohms in parallel.

equivalent resistance = 12 * 6 /(12+6) = 4 ohms.

=============

if we connect two resistors in parallel then effective resistance = 6/2 = 3 ohms.

We connect the third resistance in series. The effective resistance: 3 + 6 = 9 ohms