A gun of mass 3 kg fires a bullet of mass 30 g. The bullet takes 0.003 seconds to move through the barrel of the gun, and acquires a velocity of 100 m/s. Calculate:
a) the velocity at which the gun recoils
b) the force exerted on the gunman due to recoil of the gun.
I want the solution as well as the answer.



The Brainliest Answer!
Let m=0.03 kg be mass of bullet and it final velocity be vb
  M=3 kg be mass of gun and it's final velocity is vg
gun and bullets intial velocities are zero
well by conservation of momentum
vg=1 m s-1
so this the velocity with which gun recoils

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