# A farmer moves along the boundry of a square field of side 10 m in 40 sec. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 sec from his initial position?

2
Log in to add a comment

Log in to add a comment

The Brainliest Answer!

time taken t=2 min 20 sec=2*60+20=120+20=140 s

so distance covered is 140(0.75)=105 m

As it is square field

the man completes 2 rounds and then covers 25 m more

so the final displacement is 11.180339887498948482045868343656

he starts from A and will reach the opp. corner i.e. C in 140 sec.

displacement = AC

AC²=AB²+BC²

=10²+10²

=100+100

AC²=200

AC=√200

AC =14.14m