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2015-04-27T22:19:32+05:30

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By AM-GM inequality we have
\cos^2\Phi+\sec^2\Phi>2\sqrt{\cos^2\Phi\sec^2\Phi}=2

Thus the minimum value is \boxed{2} and this is achieved when \Phi=n\pin\in\mathbb{Z}
3 5 3
thnk u soo much :)
yw:) ahh just noticed a typo, that > should be >=
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