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2015-04-28T18:44:18+05:30

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Any quadratic function with roots -10 and -4 is of form
f(x)=a(x+10)(x+4)

Since the given vertex, (-7,-9), is a point on the graph of f(x) :
-9=a(-7+10)(-7+4)\\-9=a(3)(-3)\\-9=-9a\\a=1

Therefore the required quadratic function is f(x)=1(x+10)(x+4), which is same as \boxed{f(x)=x^2+14x+40}
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