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2015-04-30T08:15:29+05:30

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1) to get 6 ohm
       We  connect the three resistors in series.  so resistances are added to get the effective resistance:  1 + 2 + 3 = 6 Ω

2)  to get  6/11 Ω
       We connect all the resistances in parallel.  The effective resistance be R.
             1/R = 1/1 + 1/2 + 1/3 = 11/6
                 R = 6/11 Ω

3)  to get  1.5 Ω 
       We connect  1 Ω and 2 Ω in series.  Hence, resistance of the two will be 3 Ω.  Then connect the  3 Ω resistance in  parallel with the series connection of 1 Ω and 2 Ω.
               so effective resistance  =  R
                   1/R =  1/(1+2)  + 1/3 = 2/3
                   R = 3/2 Ω = 1.5 Ω

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