A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal .A massless string is wound round the cylinder with one end attached to it and other hanging freely . Tension in the string required to produce an angular accelertion of 2 revolutions s^-2 is?

2
it is easy
rope is massless
and it pulled by a force
so tension acts on rope equal to force as it massless by newton's 2nd law
so torque=Tr=Iα
Tr=m(r^2/2)α
T=mrα/2=50(0.5)=25 N

Answers

2014-05-05T11:21:52+05:30
It is easy
rope is massless 
and it pulled by a force
so tension acts on rope equal to force as it massless by newton's 2nd law
so torque=Tr=Iα
Tr=m(r^2/2)α
T=mrα/2=50(0.5)=25 N
0
2014-05-06T13:01:24+05:30
T=mr(alpha)/2
  =(50)(0.5)=25 N
1 5 1
Ys...
k this is a ques frm aipmt and in the anskey it was givvn as wrng
Then wat is d answer??
its gvn thaat 157N is d rght ans
frnd wud u gt d ans