Determine the angular acceleration of a rotating body which shows down from 500 r.m.p to rest in 10 seconds

2
by shambhavilohar98
it's rmp or rpm?

Answers

2015-05-02T20:55:03+05:30

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Body makes 500 rev in 60 sec
So, it makes 25/3 rev in 1 sec : ω₀=25/3  rev s⁻¹

ω=ω₀+αt
0=25/3+α10
-25/3=10α
α=-25/30=-5/6 rev s⁻²
2015-05-03T07:34:43+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

ω1= 2πn1                                   t=10s

=2π×500÷60                    α= ω2-ω1/t

=50π/3 rad                         =0-50π/3÷10

ω2= 2πn2                                    =-5π/3

= 2π×0

=0 rad                              angular acceleration=-5π/3