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## Answers

2cos^6+2sin^6-3cos^4-4sin^4

-cos^2-sin^2 [sin^2+cos^2 = 1]=[-1=-sin^2-cos^2]

so sin^2+cos^2=1

so ans is 1

The Brainliest Answer!

2[(cos²)³ +(sin²)³] -3[(cos²)² +(sin²)²]

on using formula a³+b³=(a+b)(a²+b²-ab)

2[(cos²+sin²)(cos^4+sin^4-cos²sin²)] -3[cos^4+sin^4]

using sin²x+cos²x=1

2[cos^4+sin^4-sin²cos²] -3cos^4-3sin^4

-cos^4-sin^4-2sin²cos²

-[(cos²)² +(sin²)² +2sin²cos²]

-[(sin²+cos²)²]

-1 is answer