# A girl running a race accelerates at 2.5m/s2 from the first 4 seconds of race. How far does she travel in this

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by rajdeepkaur3

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by rajdeepkaur3

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distance (s) = ?

Time = (t) = 4 seconds

Acceleration (a) = 2.5m/s²

Initial velocity (u) = 0 (the girl started the race)

So, by using second equation of motion we have,

s = ut + at²

s = 0*4 +

s = 0 + 20

s = 20

So, the distance travelled by the girl is 20 m.

From second equation of motion,

S=ut+1/2at^2

S=0*4+1/2*2.5*4^2

S=1/2*2.5*16

S=2.5*8

S=20 m

S=ut+1/2at^2

S=0*4+1/2*2.5*4^2

S=1/2*2.5*16

S=2.5*8

S=20 m