Answers

2015-05-06T12:42:38+05:30
Notice that \sqrt[3]{36}=\sqrt[3]{6^2}
and \sqrt[3]{6^2}\times\sqrt[3]{6}=\sqrt[3]{6^2\times 6}=\sqrt[3]{6^3}=6

That means \boxed{~\sqrt[3]{6}~} is the simplest rationalising factor of \sqrt[3]{36}
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