# A bullet fired into a fixed target loses half of its velocity after penetrating 3cm. How much futher it will penetrating before coming to rest assuming that it faces constant resistance to motion.

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After penetrating 3 cm its velocity becomes = u/2

From v2 = u2 - 2as

(u/2)2 = u2 - 2as

Thus, a = u2/8

Let further it will penetrate through distance x and stops at some point

.0 = (u/2)2 - 2 (u2/8)x

Therefore, x = 1 cm