Answers

2014-05-08T20:42:35+05:30
 \frac{7+3 \sqrt{5} }{3+ \sqrt{5} }  \frac{7-3 \sqrt{5} }{3+ \sqrt{5} }

We will multiply 3+ \sqrt{5} with numerator and denominator on both the sides.
After solving, we get  \frac{6+2 \sqrt{5} }{-2} -( \frac{36-16 \sqrt{5} }{-2}
= \frac{6+2 \sqrt{5}-36+16 \sqrt{5} }{-2}
= \frac{18 \sqrt{5}-30 }{-2}
=15-(9*root5)

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2014-05-08T23:41:20+05:30
(7)²-(3√5)²÷(3+√5)² so when u cancel 3√5²and 3√5² u will get 7² then the answer is 49
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