# What point on x axis is equidistant from the points A(7,6) and B(-3,4) ?

2
by prabodhMohan81

2015-05-07T21:34:27+05:30

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Let p be the point which is equidistant frm da pnts given
p(k,0)
Ap = Bp
√(k-7)^2+(6)^2 =√(k+3)^2 + 4^2
k=3
2015-05-07T23:33:59+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Any point on x-axis is represented by P (x, 0).  where x is a real number.

Distance AP = √[(7-x)²+(6-0)²]
Distance BP = √[(-3-x)²+(4-0)²]

if they are equal, then : 49+x²-14x + 36 = 9+x²+6x+16
20 x = 60
=> x = 3
(3, 0) is the point.