Baichung's father is 26 years older than baichung's grangfather and 29 years older than baichung.the sum of the ages of all the three is 135 years.what is the age of eachone of them

1
by aryaGole523

2015-05-09T11:32:57+05:30

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GIVEN :-

⇒Baichung ''s Father age   is 29 yrs older than baichungs grandfather  and 29 yrs older than Baichung

⇒The sum of all the three ages  =  135 yrs.

TO FIND ;-

⇒ What is the age of each one of them = ?

SOL ;-

⇒ We dont know the age of Baichung so let us take his age as x.

Baichungs fathers age = x + 29 yrs { because Baichungs father is 29 yrs                                                                elder than Baichung }

Baichungs grandfather age = x + 29 + 26 {As Baichungs grandfather is                                                                          elder than Baichung and                                                                                 Baichungs son }

In the question  it is given that their sum of their ages is 135 yrs.

⇒So we get as ,

x    +  x  +   29  +  x  +  29  +  26  =  135  { Adding all  the ages }

3   x   +   84              =  135

3x                             = 135  -   84

3x                             =51

x                               = 51/3

x                               = 17

Hence x is 17 yrs

Now apply the value of x

Baichungs age is 17 yrs

Baichungs fathers age is = 17 + 29 = 46 yrs

Baichungs grandfather age is = 17 + 29 + 26 + 72 yrs