SAnya completes work in 15 days
work done by Sania = 1 /15 part of work .
%age of work done by sania in one day = 1/15 * 100
Sanyas sister in law completes work in 10 days .
work done by sanya's sister in law in one day = 1/10 part of work.
%age of work done by sanya's sister in law in one day = 1/10*100
hence the %age of work done by sanya and her Sister in law in one day = 6.66% + 10 %
since sanya and her sister in law worked for two days , hence work done by them in 2 days =
= 16.66 *2
therfore the remaining % of work = 100 - 33.32%
since sanya completes 6.66% of work in one day .
therefore 66.66% of work will bw done by sania in 10 days.
hence it will take 10 days to finish the remaining work.