# The sum when even nos. 2+4+6+8+10..........250 is

2
by nidhiuday20

2015-05-09T10:57:11+05:30

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1st Method:
Sn (Sum of the 'n' numbers) = n/2 (2a+(n-1)d)

there given last no. is 250, so the no.of even numbers here is 250/2 i.e., 125
i.e., n=125, a (1st number) = 2, l (last number)  =  250
then,
Sn = n/2 (a+l)
= 125/2 (2+250)
= 125×252/2
= 125(126)
= 15750
therefore, the sum of all the even no.s upto 250 is 15750

2nd Method:
Sn = n/2 (2a+(n-1)d)
we got n= 250/2 = 125, a=2, d (common difference) = 2
Sn = 125/2 (2(2)+(125-1)2)
= 125(4+248)/2
= 125(252)/2
= 125(126)
= 15750
hence,
the sum of all the even no.s upto 250 is 15750
hope it helps u...
yup thank u...
wlcom
:)
2015-05-09T11:00:36+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
This is an ap with common diff.. 2
so use formula n(a1+an)/2

on this ap there will be 125 terms

so ..n=125
therefore
Sn=125(2+250)/2
=(125*252)/2
=15750
plz mark as d best if it helps u
nth term = first term + (number of terms - 1)*common difference /2
applying it in the above example , nth term = 250 , first term = 2 and common difference = 2 , substitute these values and you will find the number of terms in Arithmetic Progression ..
and Finally calculate the sum of series = (first term + last term )*number of terms / 2 !!!
enjoy !!