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## Answers

by lcm

(10x^2+8+18x)/x=(80+x^2)/x

both side multiply by x and then x cancel

now 10x^2+8+18x=80+x^2

10x^2-x^2+18x+8-80=0

9x^2+18x-72=0

taking 9 common

then x^2+2x-8=0

now it is quardratic equation

x^2+4x-2x-8=0

x(x+4)-2(x+4)=0

now x+4=0 and x-2=o

now x=-4and x=2

10 x² + 8 + 18x/x = 80/x + x

10x²+8+ 18x = 80 + x²

9x²+18x - 72 =0

divide this equation by 9

x²+ 2x - 8 = 0

use shri dhan achayra mathod to get the value of x

-b +,- √b²-4ac ÷2a

-2+,- √2² - 4 × 1 × -8 / 2 ×1

-2 + √4 + 32 ÷ 2

(-2 + √36) ÷ 2

(-2+6)÷2

x=2

now take negative

(-2 - 6) / 2

x= -4