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## Answers

*Let us assume that √5 is a rational number.*

*we know that the rational numbers are in the form of p/q form where p,q are intezers.*

*so, √5 = p/q*

*p = √5q*

*we know that 'p' is a rational number. so √5 q must be rational since it equals to p*

*but it doesnt occurs with √5 since its not an intezer*

*therefore, p =/= √5q*

*this contradicts the fact that √5 is an irrational number*

*hence our assumption is wrong and √5 is an irrational number.*
The Brainliest Answer!

*If possible, let us assume that ,***=**

*is irrational.*

**÷**

*a***×**

*b*

*b=a*

**=a**

*b*

*squaring on both sides*

(b

__=__=5 this is first equation

*is a multiple of 5,***=(5)**

*is multiple of 5,a is also multiple of 5.*

= this is second equation

****

*equate equation :- 1&2*

**25**

*l=5*****÷5=

*25l*****

*5l=***

** is a multiple of 5 and b is also multiple of 5**

****is irrational

*As , a and b are multiples of 2 which are contradictory. Our assumption is wrong.*