# Prove that √5 is irrational plzzz its urgent

2
by syedaleemuddin

2015-05-12T20:59:14+05:30
Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are intezers.
so, √5 = p/q
p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesnt occurs with √5 since its not an intezer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.
once see in our text books. they gave in this pattern only
yup mee too
do u stay in hyd
2015-05-12T21:01:41+05:30
If possible, let us assume that , is irrational.

=a÷b
×b=a
b=a
squaring on both sides
(b
=
=5      this is first equation
is a multiple of 5, is multiple of 5,a is also multiple of 5.
=(5)
this is second equation
﻿﻿equate equation :- 1&2
﻿25﻿l=5
﻿﻿25l÷5=
﻿﻿5l=
﻿﻿ is a multiple of 5 and b is also multiple of 5
﻿﻿As , a and b are multiples of 2 which are contradictory. Our assumption is wrong.
is irrational