X³ - 8 ≤ 7x - 14

x³ - 7x - 6 ≤ 0

let this equation = x³ - 7 x -6 = 0 then find the number of x whick makes it 0 then put x = 3 because if we put x = 3 we get 3³ - 7×3 - 6 = 0 rytee

then x = 3 x- 3 is a factor of this equation u already know because tumne isko 9th me pdha tha theek h na now u get it

divide this equation by x- 3

x³ - 7x - 6 ÷ x+3

do it ur self

after solving it we get (x-1)(x-2)(x+3) are the zeros of this equation

on representing these numbers on number line u get 4 cases first

∞ < x ≤ -3 second -3≤ x < 1 third 1 ≤ x <2 forth 2 ≤ x ∞

on checking it we will analyse that x ≤ - 3 then we can say that than we can say that it implies negative than value of x lies for (- ∞ to -3]

second case [-3 to 1 ] third x ≥ 2 means x lies for [2 to ∞ ] fourth x ≤ -3 means x lies from [- 3 to - ∞) we take only commen part in our answer

so commen part it (-∞ , -3] union [-3 , ∞)