This is an easy one, but requires thinking :P
a) No. of electrons in 3.6 gm of ammonium ion.
Ans. Ammonium Ion is (NH4)
This means that Ammonium Ion is formed by losing one electron.
No. of Protons is equal to Atomic number of N + 4 times atomic number of Hydrogen.
=> No. of protons in NH4 is 7 + 4 = 11
SInce NH4 is positively charged, there should be 10 electrons [so that it is plus 1 positively charged]
=> 1 atom of NH4 contains 10 electrons.
SInce 1 mole contains NA [Avogadro's number] number of ions of NH4,
1 mole of NH4 will contain NA*10 electrons.
3.6 gm of Ammonium ion is 3.6/18 moles of NH4 = 1/5 moles = 0.2 moles of NH4.
1 mole of NH4 contains NA*10 e-.
=> 0.2 moles of NH4 contains NA*10*0.2 e-
= 2NA electrons =
b) I hope you are a true science student, and can find the same for 3.2 gm of Methane, that will be
The above is the no. of electrons of 3.2 gm of CH4.
I think we have got same answers, isn't it ? :-)