# A particle moves 3m north,then 4 metre east and finally 6 metre south.calculate the displacement?

2
by sureshmr36

2015-05-14T20:24:57+05:30

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I have attached  a image for better understanding..after drawing the dotted line from A to B you can see a square is formed so AB =4 cm. and BE = 6-3 cm= 3cm. So in triangle ABE , with pythagoras theorem AE^2 = BE^2 + AB^2 = 16 + 9 = 25 . Therefore AE = root 25 = 5 cm...which is equal to displacement...
image?
i am sorry ...i cannot find a option to draw a image
you may see now it is there!
thank you :)
You are welcome
2015-05-14T23:41:21+05:30

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E^2 = BE^2 + AB^2 = 16 + 9 = 25 . Therefore AE = root 25 = 5 cm.. is the answer